2/21/08 midterm solutions! (Fig1) read 10.1,10.2 homework is 10.1,2,7,8 fourier series Continuous Time x(t)=sum(Dne^(jwnt)) x must be periodic with w as the period Discrete Time x[n]=sum(Dne^(jrOMEGAn)) x must be periodic with period No, OMEGA = 2pi/No OMEGA=wT can shift r by No and make no difference on the result so there are only No unique terms changes equation to x[n]=sum(Dne^(jrOMEGAn)) Dn = sum(x[n]e(-jrOMEGAn)) = sum(Dnsum(e^(j(r-m)OMEGAn))) if r-m = 0, ans is No if r-m!=0, its a geometric series since the value can never be greater than 1, so sum(e^(j(r-m)OMEGA)^n) = (e^(j2pi(r-m))-1) / (e^(j(r-m)OMEGA)-1) = 0 Dm = 1/No *sum(x[n]e^(-jmOMEGAn)) example (Fig2)